Analyze the Binary Tree Structure
The decision tree classifier has an attribute called tree_
which allows access to low level attributes such as node_count
, the total number of nodes, and max_depth
, the maximal depth of the tree. It also stores the entire binary tree structure, represented as a number of parallel arrays. Using these arrays, we can traverse the tree structure to compute various properties such as the depth of each node and whether or not it is a leaf. Below is the code to compute these properties:
import numpy as np
n_nodes = clf.tree_.node_count
children_left = clf.tree_.children_left
children_right = clf.tree_.children_right
feature = clf.tree_.feature
threshold = clf.tree_.threshold
node_depth = np.zeros(shape=n_nodes, dtype=np.int64)
is_leaves = np.zeros(shape=n_nodes, dtype=bool)
stack = [(0, 0)] ## start with the root node id (0) and its depth (0)
while len(stack) > 0:
## `pop` ensures each node is only visited once
node_id, depth = stack.pop()
node_depth[node_id] = depth
## If the left and right child of a node is not the same we have a split
## node
is_split_node = children_left[node_id] != children_right[node_id]
## If a split node, append left and right children and depth to `stack`
## so we can loop through them
if is_split_node:
stack.append((children_left[node_id], depth + 1))
stack.append((children_right[node_id], depth + 1))
else:
is_leaves[node_id] = True
print(
"The binary tree structure has {n} nodes and has "
"the following tree structure:\n".format(n=n_nodes)
)
for i in range(n_nodes):
if is_leaves[i]:
print(
"{space}node={node} is a leaf node.".format(
space=node_depth[i] * "\t", node=i
)
)
else:
print(
"{space}node={node} is a split node: "
"go to node {left} if X[:, {feature}] <= {threshold} "
"else to node {right}.".format(
space=node_depth[i] * "\t",
node=i,
left=children_left[i],
feature=feature[i],
threshold=threshold[i],
right=children_right[i],
)
)