What happens if 'isPrime' is still true after the for loop in the prime number finding logic?

In the prime number finding logic, if the isPrime flag remains true after the for loop, it indicates that the number being checked is a prime number. This is because the loop checks for divisibility by all integers from 2 to number - 1. If no divisors are found (i.e., the flag is not set to false), it confirms that the number is only divisible by 1 and itself.

Example Logic:

Here’s a simplified explanation of how the logic works:

1. Initialization: Set a flag (e.g., isPrime) to true at the beginning.
2. Loop: Iterate through potential divisors from 2 to number - 1.
   • If the number is divisible by any of these divisors, set the flag to false and exit the loop.
3. Check Flag: After the loop, check the value of the flag:
   • If isPrime is still true, print that the number is prime.
   • If isPrime is false, print that the number is not prime.

Example Code Snippet:

void isPrime(int number) {
    int isPrime = 1; // Assume number is prime
    for (int i = 2; i < number; ++i) {
        if (number % i == 0) {
            isPrime = 0; // Not prime
            break; // Exit loop
        }
    }
    if (isPrime) {
        printf("%d is a Prime Number\n", number);
    } else {
        printf("%d is Not a Prime Number\n", number);
    }
}

In this example, if isPrime remains 1 (true) after the loop, it indicates that no divisors were found, and thus the number is prime.