Is the script able to handle any number of arguments?

Yes, the script can handle any number of arguments. The last version of the script uses the $@ special variable to loop through all provided arguments, making it flexible enough to process any number of inputs. Here's a brief overview of how it works:

#!/bin/bash

echo "Total number of arguments: $#"
echo "All arguments:"

count=1
for arg in "$@"; do
 echo "Argument $count: $arg"
 count=$((count + 1))
done

This script will display all arguments passed to it, regardless of how many there are.