Sure! Let's consider an example of a 32-bit single-precision floating-point number represented in binary.
Example:
Let's take the decimal number -5.75 and see how it is represented in IEEE 754 format.
-
Convert to Binary:
- The integer part (5) in binary is
101. - The fractional part (0.75) in binary is
0.11(since 0.75 = 0.5 + 0.25). - Therefore, -5.75 in binary is
-101.11.
- The integer part (5) in binary is
-
Normalize the Binary:
- Normalize it to scientific notation:
-1.0111 × 2^2.
- Normalize it to scientific notation:
-
Determine the Sign Bit:
- Since the number is negative, the sign bit is
1.
- Since the number is negative, the sign bit is
-
Calculate the Exponent:
- The exponent is
2. In IEEE 754, we use a bias of 127 for single precision. - So, the biased exponent is
2 + 127 = 129, which in binary is10000001.
- The exponent is
-
Determine the Mantissa:
- The mantissa is the fractional part after the binary point in the normalized form. For
1.0111, we take0111and fill the remaining bits with zeros to make it 23 bits:01110000000000000000000.
- The mantissa is the fractional part after the binary point in the normalized form. For
Final Representation:
Putting it all together, the 32-bit representation of -5.75 in IEEE 754 format is:
- Sign Bit:
1 - Exponent:
10000001 - Mantissa:
01110000000000000000000
So, the complete binary representation is:
1 10000001 01110000000000000000000
In hexadecimal, this would be represented as 0xA1C00000.
