How does the AWK command filter requests with a 404 status code?

The AWK command filters requests with a 404 status code using the following syntax:

awk '{count[$6]++} END {for (code in count) print code, count[code]}' server_logs.txt | sort -n

In this command:

1. $6 refers to the sixth field in each line of the input, which typically contains the HTTP status code.
2. count[$6]++ increments the count for each occurrence of the status code found in the sixth field.
3. END {for (code in count) print code, count[code]} executes after processing all lines, printing each status code and its corresponding count.
4. | sort -n sorts the output numerically.

To specifically filter for 404 status codes, you can modify the command like this:

awk '$6 == "404" {print}' server_logs.txt

This command will print only the lines where the sixth field equals "404".