How are string positions indexed in this syntax?

In Java, string positions are indexed starting from 0. This means that the first character of a string is at index 0, the second character is at index 1, and so on. For example, in the string "Hello":

• H is at index 0
• e is at index 1
• l is at index 2
• l is at index 3
• o is at index 4

You can access a character in a string using the charAt() method. For example:

String str = "Hello";
char firstChar = str.charAt(0); // 'H'
char secondChar = str.charAt(1); // 'e'

If you try to access an index that is out of bounds (less than 0 or greater than or equal to the string length), it will throw a StringIndexOutOfBoundsException.